Liquids and Melts
Books
D Tabor – Gases, Liquids and Solids CUP 1991 (3rd edition)
JN Murrell and AD Jenkins Properties of Liquids and Solutions
We have already seen how to characterise the structure of amorphous materials experimentally using different types of scattering.
At this level of structure, liquids are essentially the same as glasses – it is in their dynamics that they differ.
So the simplest model of a liquid assumes 'hard sphere' interactions – i.e. repulsive forces dominate.
As with glasses, computer simulations are often used to model structure.
Density of 'random close-packed' structure –
i.e. the structure in which there are no spaces large enough to fit another
atom – is 0.638 compared with 0.7405 for
cubic close packing.
The density of a liquid is therefore only ~10% different from
a crystalline solid – little volume change on
melting.
Properties of Liquids
· Unable to withstand shear stresses – liquids flow, but they may exhibit instantaneous shear modulus if they take a finite time to respond.
· Have a critical point, when liquid and gas phase are indistinguishable.
· Can withstand negative pressures, although ultimately will cavitate.
· Have well defined volumes, and relatively strong interatomic cohesive forces.
· Nearest neighbour organisation not very different from solid, and coordination number only drops by ~10% , say from 12 to 10, upon melting.
Melting Transition
1st order phase change, with associated latent heat and change in entropy.
Magnitude of changes at Tm quite small, compared with gas-liquid transition, except for change in fluidity.
There are various approaches to the melting transition, but it is not well understood.
Lindemann Criterion:
(An early, simple and widely
used criterion to predict melting points).
Assumes solid melts when rms amplitude of vibration exceeds critical fraction
of lattice spacing.
[Note that melting cannot be
explained simply by the interatomic potential, which can only predict solids
and gases.]
<u2>1/2
= f ao
where f appears to depend on
lattice.
Solid |
Tm calculated (K) |
Tm experimental(K) |
Lead |
400 |
600 |
Silver |
1100 |
1270 |
Iron |
1800 |
1800 |
Tungsten |
4200 |
3650 |
Sodium chloride |
1200 |
1070 |
Quartz |
1900 |
2000 |
Dislocation Theories of Melting
We have seen how around dislocation cores, the packing of a crystal is severely disrupted.
This model assumes that in the liquid every atom is situated within a dislocation core – to give non-regular packing overall.
Thus the liquid is imagined to be saturated with dislocations.
Note that the stored energy of dislocations in a heavily cold-worked material with high dislocation density can start to approach the latent heat of melting.
Must have an energy penalty for dislocation creation which decreases as the number of dislocations already present increases.
This can occur because dislocation dipoles can be formed with screening of long range fields.
If dipole separation comparable with core diameter
Total
energy/pair ~ 2 x core energy
Using the fraction c of
dislocations present as a parameter (c=1 fully saturated) find lowest free energy state for
c=0 at T<Tm
and c=1 for T>Tm
As dislocations proliferate,
solid loses its rigidity.
This can be studied by
computer simulation, including using a molecular dynamics approach to study how the crystal structure changes with
annealing.
However in practice surfaces
(grain boundaries, free surface etc) may also matter – melting tends to
initiate there and spread into the bulk.
At late stage of
melting, many dislocations present and crystal structure not really visible
Kinetics of Crystallisation
Will now look at a more general version of what we first considered for polymer crystallisation.
Tm occurs when Gibbs free energy of solid and liquid are identical.
This neglects any specific
crystallography associated with crystal nucleus.
For now we will consider only homogeneous nucleation ie ignore the role of surfaces and seeds.
On solidifying the entropy changes by an amount DSm.
where DHm is the latent heat of fusion released upon crystallisation and is measurable by experiment.
In general there is a degree of supercooling, but if this is small we can integrate the equation for DSm to yield
(This assumes the derivatives of free energy in solid and liquid phase don't change much with temperature, so that they can be approximated by straight lines.)
If you create a spherical droplet of a crystal (ignoring crystallography) of radius r in the liquid melt we can work out the total free energy change.
It will involve two terms
· bulk, associated with change in free energy DGb(DT)
·
surface – associated
with the interface.
bulk term surface
term
gSL is the
interfacial energy of solid/liquid interface
The dependence of the total free energy change
on droplet radius can be plotted.
A critical nucleus size
r* exists when
This occurs when
Þ
Droplets smaller than this are
energetically unfavourable, shrink and disappear.
For these the energy gain on
the formation of small droplets is insufficient to offset the interfacial
energy cost.
Larger droplets grow.
DG* is effectively an
energy barrier to droplet formation
r*
is largest at T~Tm - as the supercooling increases smaller droplets
are stable.
One
can evaluate the probability of a droplet of radius r forming in terms of the
activation barrier.
P(r) ~ exp -DG(
r)/kT
Number
of critical clusters per N atoms is
N* = N exp -DG*/kT
Experiments
to test these ideas are very difficult to do – in general heterogeneous rather
than homogeneous nucleation will occur.
Classical
experiments looked at very small particles nucleating in the melt.
In
classical experiments small particles nucleating in the melt were looked at, in
the belief that some of these would have nucleated homogeneously.
The
rate R = K exp - DG*/kT
The
prefactor K takes into account the necessary diffusive processes required to
allow a droplet to grow.
In
general the rate will be determined by the exponential, but there are some
systems where the necessary diffusion becomes kinetically limited
e.g
when the viscosity of the liquid becomes very high, following the Vogel-Fulcher
law we discussed before.
If
As
To approached h ® ¥.
Then
nucleation will become kinetically inhibited and it is favourable for a glass
to form.
Example – Tin
Melting point 505.7K
gSL 54.5
x10-3 J m-2
DHm 4.4 x 108
J m-3
Þ DG* =
This
can be plotted to show how rate depends on temperature.
This can be plotted to show how
rate depends on temperature.
Heterogeneous Nucleation
For heterogeneous nucleation have to correct this theory, to allow for change in energy penalty when we nucleate on a surface.
On a particle surface P, a droplet nucleus (S) may form.
q = contact angle
Young's
equation defines contact angle by balancing the different interfacial energy
terms.
(Recall
surface tension º line tension/unit
length.)
gSLcosq = gPL- gPS
[Note
the condition for complete wetting is that
gSL < gPL- gPS so that
there is no real solution for q; then the drop
completely wets the surface. These
ideas hold for liquids wetting a surface too.]
In
order to calculate the energy cost of nucleation we need to know the volume and
surface area of such a spherical cap.
For
a cap formed from a sphere of radius r
V =
1/3 pr3(1 - cosq)2 (2 + cosq)
SPS = pr2
sin2q
SSL = 2pr2 (1-cosq)
[These
equations reduce to the previous ones when q = 180˚,
ie for homogeneous nucleation of a spherical drop.]
When
such a spherical cap is created, change in free energy becomes
new PS
interface PL interface lost
Last
two terms can be rewritten as gSLcosq pr2sin2q from Young's equation.
Differentiating
to solve for r* and rearranging, can show that all terms involving q
disappear and
For contact angles <90˚ this leads to a substantial reduction in DG*, and hence in the supercooling necessary for
nucleation.
This
is why surfaces and dust particles can be so effective at favouring
solidification.
When
the particle is a seed crystal of the same material as the melt gPS=0 and gSL=gPL (no
interface)
Þ
cosq = 1 and the contact angle is zero.
Then
DG* = 0 and no activation energy is required.
Melting
Supercooling is the rule when observing crystal nuclei forming from the melt.
This is not the case when crystals are heated to their melting point.
In general you cannot superheat a solid – why?
Consider a liquid droplet forming as it melts on a solid surface with vapour
above.
Contact angle given by the same type of equation as previously, but now known as the Young-Dupré equation.
gSV - gSL = gVL cosq
Uniform
wetting of the surface occurs when the contact angle goes to zero
gSV - gSL > gVL
If
this inequality holds at the triple
point, the solid will be covered by a thin layer of its own melt.
In
general this inequality is found to be true for most solid/liquid pairs.
The
solid and liquid are chemically identical (and number of nearest neighbours not
very different) so that gSL is
usually small.
Liquid
surface energies (ie with the vapour phase) are usually less than solid surface
energies because the fluidity of the former allows more rearrangements to
occur.
Premelting
usually occurs as the solid is heated towards Tm.
A thin layer of liquid forms on the surface
below Tm and then increases to ¥
at Tm.
Can
be studied experimentally:
·
Grazing angle X-ray
diffraction
·
Ion beam channelling.
Grazing
Angle X-ray Diffraction
For
sufficiently low angles of incidence very little penetration into the material
(evanescent wave does not propagate far).
Only
near surface structure seen.
Diffraction
spots near the surface disappear below Tm: surface melting occurs.
Ion
Beam Channelling
Melting
always starts at the surface, and becomes a bulk phenomena at Tm.
Examples of premelting phenomena:
·
Formation of ice from
snow to give glaciers.
·
Powder sintering below Tm.